Dice Roller

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5d6 - 50 => [2, 6, 5, 2, 1] = -34
Worked for me.
Dice Rolls => Results = Total
5d6 - 50 => [2, 6, 5, 2, 1] = -34
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To note, in the Classic World of Darkness system (at least), any 1's you roll automatically subtract from the highest succeeding dice that you roll.

So if you roll [1, 2, 3, 6, 9, 9, 10, 10] and your target difficulty is 8, the actual result would be: [2, 3, 6, 9, 9, 10] (The 1 and the other 10 cancelled out) to a final sum of: 3 Successes (9, 9, and 10) with a possible explode on the 10.

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